Saturday, February 20, 2010

Hgo Lipo I Chemical Reactions, Help? ?

Chemical Reactions, Help? ? - hgo lipo i

You can, if I got it right this and let me explain what the formula would be more appropriate if it is false. Thank you! :)

1. Ag + S -> AGS = Synthesis
2. K + O -> KO = Synthesis
3. Mg + HCl -> MgCl + H = Simple Moving
4. Al + HCl -> H = + ALCL-way
5. HgO -> Hg + O = Decomposition
7. Br + KI -> I + KBR = Single Displacement
8. Al + + + HSO, -, H + Al (SO) = Simple Moving
9. CuSO + Mg -> Cu + = Simple Moving MgSO
10. HCO + Al (OH) -> HO + Al (CO) = Simple Moving
11. HPO + LiOH -> HO + LIPO = Simple Moving

2 comments:

Anonymous said...

1. must Ag + S -> Ag (sub2) SS because it has a charge of -2
2. The product may only K (sub2) OO, because it has a charge of -2
3. MgCl (sub2) Magnesium is a fee of 2
4. ALCL (SUB3) Aluminum has 3
5. right
6. No: P
7. I may be wrong, but I think it will not happen because the same reaction of bromine potassium can displace
8.Correct
9. right
10. This is not a movement but a movement of 2 dual elements are moved.
11. Double shift

I just noticed that never bothered to figures will be brought to them, a necessity

Anonymous said...

They seem to difficulties balancing the workload and relationships:

1. 2 Ag + S -> Ag2S = summary
(S has a weight of 2 and GA with a penalty of 1, so it takes 2 to balance loads AG)

2. 2C + O -> K2O = Summary
(O is a fee of 2 and K is a fee of 1, so you need to 2 K load balancing)

3. Displacement of Mg 2 + HCl -> MgCl2 + H2 = single
(H is a diatomic gas, which must be accompanied by something else, and Mg is a fee of 2, so you need to load balancing to 2 Cl)

4. Moving 6HCl + 2Al -> 3H2 + = 2AlCl3 single
(H is a diatomic gas, which must be accompanied by something else, and Al has a charge of 3, it must be 3 Cl-load-balancing)

5. 2HgO -> 2HG + O2 = Decomposition
(Or is a diatomic gas, which must be accompanied by something else)

I can help you, but you should try, based the rest yourself, what has helped me to understand. think you should talk to your teacher and try to get help.

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